Lara is pregnant!

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Re: Lara is pregnant!

Post by Rhasputin on Mon Mar 19, 2012 2:00 pm

I also like his sister. I just like the dark splatters on top of the yellow splatters.
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Re: Lara is pregnant!

Post by Mrs. Beach on Mon Mar 19, 2012 2:59 pm

SO DO I! It's really cool! That's what the Brindle Empire is all about! Those two colors and white. Wheeeee!
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Re: Lara is pregnant!

Post by LittleSniffs on Mon Mar 19, 2012 3:46 pm

Wow those are soo cute! Love the colors!
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Re: Lara is pregnant!

Post by Mrs. Beach on Mon Mar 19, 2012 4:24 pm

The Imperial Flag of Mrs. Beach's Brindle Empire is orange, beige, and white!
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Re: Lara is pregnant!

Post by doganddisc on Mon Mar 19, 2012 4:53 pm

Gorgeous babies, Mrs. Beach!!!! Congrats Happy
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Re: Lara is pregnant!

Post by snukb on Mon Mar 19, 2012 8:20 pm

I just can't get over how much bigger show type mice are over pet type mice. I keep looking at those babies thinking how HUGE they are! So adorable! The white one with just a few cream spots is definitely my favorite.
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Re: Lara is pregnant!

Post by pamszoo on Mon Mar 19, 2012 10:35 pm

awww I love them! adorable Happy
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Re: Lara is pregnant!

Post by Mrs. Beach on Thu Mar 22, 2012 2:23 am

They just opened their eyes. Still can't tell if they're splashed or tri (have white areas). Need to take more current pix and ask you-all. The high white apparently pied brindle doe has developed some dark smudges on her orange spots. Whether they are parts of brindle stripes or unsplashed areas, I do not know.

The splashed brindles have whitish areas, orangeish areas, and dark smudgey areas. I figure the whitsh areas are the diluted parts, the orangeish areas are the splashed parts, and the dark areas are...? OK, I can see a beige brindle being splashed and being almost white and orange. The almost white is the diluted color. The orange is the splashed color. The dark areas are...not horozontal, so they can't be stripes. Are they the base color of the mouse, either agouti or black? But, but, but, that's what the orange parts are! So then would the whitish parts be s/s? It's all streaked together. Weird. I've gotta take pix and show you!
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Re: Lara is pregnant!

Post by Mrs. Beach on Thu Mar 22, 2012 2:50 pm

Day 12:



Can anybody explain genetically what those dark streaks are? One would assume they are brindle stripes, the Super Line has the Asplodamouse A^vy gene which is extremely undermarked. Supergirl was undermarked. Lara...well...lara does have some stripes. But still, the dark streaks are running parallel to the mice's spines, not perpendicular to them. Why?
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Re: Lara is pregnant!

Post by Stina on Thu Mar 22, 2012 3:07 pm

It's probably brindle sootiness. Remember that the pattern of a brindle is largely environmental, and not just genetic. Differences in diet from the grandparents and parents will affect how the offspring are brindled.

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Re: Lara is pregnant!

Post by Mrs. Beach on Thu Mar 22, 2012 4:13 pm

So I've got stripes back! Hurrah! So the white areas are the diluted parts and the orange-and-black areas are the splashed parts. Got it! But if the white parts are the diluted parts, that means not a single one of these bubs is beige! Drat! waitaminnit...maybe that's what the satin bub who is so dark is...beige!

I have a bona fide c^e/c^e S/s buck named Don. Would it make sense to breed the splashed brindle doe (who also carries s) to him and then breed only from their beige brindle tri or splashed offspring? I'm working with two recessives and it's hard to keep both pairs together! (Come to think of it, that would assure c^e/c^e in every mouse, but not s/s. Hmmm.) (Well, I'd rather have c^e/c^e in every mouse than s/s. At least they'll be orange and beige.) Hey! Maybe I should breed the high white brindle (tri?) (who is */c^e s/s) to the c^e/c^e S/s buck! And then cross in Spl, which should be easier because it's dominant? Hipsebah's got some beige tri babies I could use. Geeze! What's a good strategy?
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Re: Lara is pregnant!

Post by WindyHill on Thu Mar 22, 2012 4:58 pm

They are so pretty!
Congrats
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Re: Lara is pregnant!

Post by Stina on Thu Mar 22, 2012 5:21 pm

Keep in mind that a c^e/c^e brindle will NOT have any actual beige on it....it will be cream/off white....beige is diluted black and is a darker grayier color...lol orange won't dilute to a brownish gray, it will dilute to a yellowy, creamy color. Beige may not be the best term to use for a c^e/c^e diluted brindle...I'd call it extreme dilute brindle myself

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Re: Lara is pregnant!

Post by doganddisc on Thu Mar 22, 2012 5:43 pm

They are so gorgeous!
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Re: Lara is pregnant!

Post by Mrs. Beach on Thu Mar 22, 2012 6:19 pm

Stina, I thought an extreme dilute brindle (good name for them!) would have orange brindle patches and beige brindle patches (like Mrs. Beach's coat) and white patches. I thought that's what we talked about long ago when I was asking a billion questions to see if it was possible. Why suddenly yellowy creamy color instead of beige? Mrs. Beach was A^vy/* c^e/c^e and she was beige. I don't get it. Something to do with the splashed gene? And how would I get beige patches on a brindle tri? c^e/c^ch?

...You're going to tell me that A^vy dilutes the mela**anins--the blacks and blues--so it is an epistatic relationship between c^e and A^vy, RIGHT?
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Re: Lara is pregnant!

Post by LittleSniffs on Fri Mar 23, 2012 12:20 am

They are so cute, and I love the color!!!
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Re: Lara is pregnant!

Post by Mrs. Beach on Fri Mar 23, 2012 12:53 am

Stina wrote:Keep in mind that a c^e/c^e brindle will NOT have any actual beige on it....it will be cream/off white....beige is diluted black and is a darker grayier color...lol orange won't dilute to a brownish gray, it will dilute to a yellowy, creamy color. Beige may not be the best term to use for a c^e/c^e diluted brindle...I'd call it extreme dilute brindle myself

So Stina, how are snow tigers like Mrs. Beach made? I thought they were A^vy/* c^e/c^e. Enlighten me!
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Re: Lara is pregnant!

Post by Mrs. Beach on Fri Mar 23, 2012 1:03 am

ASKING FOR PEOPLE'S OPINIONS: Are any of the splashed brindles (all but the high white one) tri? Does anyone see verifiable white, or patterns which indicate s/s is present?
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Re: Lara is pregnant!

Post by Mrs. Beach on Sat Mar 24, 2012 1:21 am

Day 16. I think I have FOUR tricolor brindles! The high white one is most like my breeding goal. I am breeding towards pools of color.


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Re: Lara is pregnant!

Post by LittleSniffs on Sat Mar 24, 2012 4:07 am

They are so pretty! Great job Happy
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Re: Lara is pregnant!

Post by Mrs. Beach on Sat Mar 24, 2012 3:36 pm

Day 17, the female spashed/tri brindle (I need to name these babies!):




She does look so much like she has beige or darker parts--unsplashed, diluted streaks. Her brother is similar, though mostly in one streak running just to the right of his spine.
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Re: Lara is pregnant!

Post by Mrs. Beach on Sun Mar 25, 2012 12:43 am

Mrs. Beach wrote:Day 16.

THESE BUBS NOW HAVE NAMES!

(LEFT TO RIGHT)
Dandelion, splashed/tri brindle buck
Burns, splashed/tri overmarked satin brindle buck
Honeysuckle, splashed/tri brindle doe
Chrysalis, high white pied brindle doe

I was thinking of monarch butterfly chrysalises that has a row of gold spots around them. Chrysalis likewise has a row of gold (orange) spots!
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Re: Lara is pregnant!

Post by Mrs. Beach on Tue Mar 27, 2012 6:45 pm

Day 20.

Splashed bit on Chrysalis' butt. She's an extreme dilute brindle tri!



Dandelion:



Burns:


Honeysuckle's p[ix are coming. My student is here!


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Re: Lara is pregnant!

Post by Stina on Tue Mar 27, 2012 7:37 pm

Stina, I thought an extreme dilute brindle (good name for them!) would have orange brindle patches and beige brindle patches (like Mrs. Beach's coat) and white patches. I thought that's what we talked about long ago when I was asking a billion questions to see if it was possible. Why suddenly yellowy creamy color instead of beige? Mrs. Beach was A^vy/* c^e/c^e and she was beige. I don't get it. Something to do with the splashed gene? And how would I get beige patches on a brindle tri? c^e/c^ch?

...You're going to tell me that A^vy dilutes the mela**anins--the blacks and blues--so it is an epistatic relationship between c^e and A^vy, RIGHT?
sorry for the delay...I missed the responses somehow!

As A^vy dilutes the mouse to yellow/orange with black stripes...any of the c-dilutes will be working on both colors. c^e does not remove pheomelanins (yellow) entirely, so you will still have some yellow to any diluted areas, thus a cream, rather than beige, color. Mrs. Beach was likely c^ch/c^e I think. I'm trying to think how things would dilute... for c^ch/c^ch brindle you would have nearly black stripes on a nearly white background, since the background on an undiluted brindle is orange, and c^ch removes close to all orange. It wouldn't produce much contrast in a tri. c^ch/c^e would produce dark mud stripes probably still on a close to white background...but maybe not as diluted as c^ch/c^ch. c^ch/c or c^ch/c^h would produce light mud stripes on a close to white background. c^e/c^e would produce beige stripes on a cream background. c^e/c or c^e/c^h would produce very very light stripes on a close to white background. I think you had anded up choosing c^e/c^e b/c it should produce the best balance of contrast on a tricolor with predictable results. Assuming Mrs. Beach was c^ch/c^e, it would require more mice for breeding since you'd either be getting a lot of c^ch/c^ch mice and a lot of c^e/c^e mice or you'd have to cross c^ch/c^ch mice to c^e/c^e mice to get all c^ch/c^e.

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Re: Lara is pregnant!

Post by Mrs. Beach on Wed Mar 28, 2012 3:12 pm

As always, Stina, you give complete, distilled information. I must cogitate on this!
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